Position vs time graph of a cart starting at x=0 at t=5s. The actual motion is in blue, the motion extrapolated back to t=0 is in red. |
It might be easier to estimate the parameters if one expresses the FUNKE in a different way: use t0, which is the time at which the parabola reaches its extreme value (either maximum or minimum) and xp, the position at that time. In other words, the time and the position of the parabola's apex. Then the FUNKE becomes:
Your fitting parameters are xp, t0 and a, and a is the same as in the original form. Notice that v0 is not in this equation because at the apex the velocity is zero.
You can do your modelling assignment with this equation. It is another correct way of expressing motion with constant acceleration. As long as you explain what you're doing you'll get full credit if it's right and partial credit if it's wrong and we understand what you're getting at.
There are many right ways of doing most problems. Unfortunately, there are many more wrong ways.
Can you find the mathematical relationship between x0, v0, a and xp, t0, a ?
Expand and collect termsfrom which
For example if a = 1 m/s2 and the curve reaches the minimum xp = 0 at t0 = 5 s.
What is x0 and v0?
and v0 = −10 m/s
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